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2 years ago

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Which equation represents this statement? Fourteen less than three times a number is fifty-two. A) 3x −14 = 52 B) 3x + 14 = 52 C

) 52 −14 = 3x D) 52 −3x = 14

1 answer:

zalisa [80]2 years ago

5 0

Answer:

A

Step-by-step explanation:

This sentences implies that to a number multiplied by 3 ( three times a number) 14 needs to be subtracted.

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2/5y - 4 + 7 - 9/10y with steps

Lesechka [4]

Let's simplify step-by-step.

2/ 5 y−4+7− 9 /10 y = 2 /5 y+−4+7+ −9 /10 y

Combine Like Terms: = 2 /5 y+−4+7+ −9 /10 y

(2 /5 y+ −9 /10 y)+(−4+7) = −1 /2 y+3

Answer: = −1 /2 y+3

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2 years ago

WILL MARK YOU BRAINLIEST

anzhelika [568]

Answer:The area is 14306. 625 cm.

Step-by-step explanation:

To find the area of the circle, we will need to find the diameter and find the radius.

So we know the circumference is 423.9 m and we know to get the circumference, you will need to multiply pie by the diameter .

so now we need divide the circumference by pie to find the diameter.

423.9/ 3.14 = 135 so 135 is the diameter.

To find the radius we need to divide the diameter by 2.

135/2 = 67.5

Now is time to find the area which uses the formula A= nr^2

A = 3.14 * 67.5^2

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2 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = <u><em>percentage of employed workers who have registered to vote.</em></u>

$p_2$ = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u> = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

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2 years ago