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bezimeni [28]
3 years ago
8

Draw and label a tape diagram to subtract 10, 20, 30

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
This isnt something I can do... But draw and label a tape diagram that goes from 0 to 30. 
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Given f(x)= 2x²+4x-6 and g(x)=2x-2, find each function
valkas [14]
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3

2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10

3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
5 0
3 years ago
Ricard lost 6 golf balls while playing yesterday. He bought a box of 12 golf balls ,then lost 4 on the course today . He now has
viktelen [127]

16, first you need to add on the four he lost to the 18 he ended with.

4 0
3 years ago
2] The Patel family drinks a total of 360 fijuid ounces of water a day. How many cups of water is
adell [148]

Answer:

45 cups

Step-by-step explanation:

8 ounces are in 1 cup.

360oz/8oz=45 Cups

3 0
2 years ago
Read 2 more answers
The difference between the solutions to the equation x squared = a is 30. What is a? Show that your answer is correct.
Trava [24]
You said that 'A is 30' right there in the equation 
so it would be 
Xsquared=30
5 0
3 years ago
The angle θ1\theta_1 θ 1 ​ theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end
melomori [17]

Answer:

\dfrac{3\sqrt{13}}{11}

Step-by-step explanation:

Given that the angle \theta_1  is located in Quadrant II; and

\cos(\theta_1)=-\dfrac{2}{11}

In Quadrant II, x is negative and y is positive.

\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\

To find \sin(\theta_1), we first determine the opposite angle of \theta_1.

This will be done using the Pythagoras theorem.

Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}

Therefore:

\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}

6 0
3 years ago
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