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1 answer:
Answer:
b) The Pie Eating Contest would be more skewed
Step-by-step explanation:
Let's begin by drawing out a frequency distribution table for the given information:
<u>Pie Eating Contest</u>
Age Group (Years) Frequency
0 - 19 20
20 - 39 40
40 - 59 60
60 - 79 50
If all 20 people (aged 75 - 79) joined this event, the frequency tables changes to become:
<u>Pie Eating Contest (2)</u>
Age Group (Years) Frequency
0 - 19 20
20 - 39 40
40 - 59 60
60 - 79 70
<u>Chili Cookoff</u>
Age Group (Years) Frequency
0 - 19 30
20 - 39 50
40 - 59 40
60 - 79 10
If all 20 people (aged 75 - 79) joined this event, the frequency tables changes to become:
<u>Chili Cookoff (2)</u>
Age Group (Years) Frequency
0 - 19 30
20 - 39 50
40 - 59 40
60 - 79 30
The graphical representation of each event is attached as a picture
A histogram is skewed if its frequency distribution is biased to one side (either to the left or to the right). This implies that the histogram is not evenly distributed. When the histogram is cut into equal halves, the left side and the right side look unidentical.
A histogram is symmetrical if its frequency distribution is neither biased to the right or to the left. It implies that the histogram is evenly distributed across the left and the right side. When the histogram is cut into equal halves, the left side and the right side look identical.
When we consider the event in which all 20 people join the Pie Eating Contest, the histogram becomes skewed to the right.
When we consider the event in which all 20 people join the Chili Cookoff, the histogram becomes more symmetrical
We will observe that when all 20 people joined the Pie Eating Contest, the histogram becomes more skewed to the right and less symmetrical. On the other hand, if all 20 people join the Chili Cookoff, the histogram becomes more symmetrical and less skewed
We will observe that when all 20 people joined the Pie Eating Contest, the histogram becomes more skewed to the right and less symmetrical. On the other hand, if all 20 people join the Chili Cookoff, the histogram becomes more symmetrical and less skewed
<u>Hence, the correct answer is option b) The Pie Eating Contest would be more skewed</u>
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Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:
X = 790:
Z = 1.8
Z = 1.8 has a p-value of 0.9641.
X = 575:
Z = -2.5
Z = -2.5 has a p-value of 0.0062.
0.9641 - 0.0062 = 0.9579.
0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
More can be learned about the normal distribution at brainly.com/question/4079902
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Answer:
<em>b</em><em> </em><em>=</em><em> </em><em>44</em><em> </em><em>feet</em><em> </em>
Step-by-step explanation:
BY Pythagorus theorem :-
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