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4 years ago

What is a common factor (a whole number that can fit into both of them) of 142 and 135?

1 answer:

7 0

142 = 2 * 71
Factors of 142 = 1,2,71,142

135 = 3 * 3 * 3 * 5
factors of 135 = 1, 3, 5, 9, 15, 27, 45, 135

Common factor of 135 and 142 = 1

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3 years ago

There is a 30% chance that Jerry will have to wait for the bus for more than five minutes to go to office. What is the probabili

Elina [12.6K]

The probability that he does not wait for more than five minutes all 5 days this week is 0.16807

<h3>How to determine the probability?</h3>

The probability that he waits for more than 5 minutes is:

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3 years ago

Pls solve part b) iii thanks

Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees