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mariarad [96]
3 years ago
13

What is P = 2a + 2b for a

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

The answer to b is:

b = p/2 - a

the answer to a is:

a= p - 2b/2

I am also homeschooled :-)

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Which transformations are needed to change the parent cosine function to y = 0.35 cosine (8 (x minus startfraction pi over 4 end
Nataliya [291]

The transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

  • vertical stretch of 0.35
  • horizontal compression of period of \dfrac{\pi}{4}
  • phase shift of  \dfrac{\pi}{4} to right

<h3>How does transformation of a function happens?</h3>

The transformation of a function may involve any change.

Usually, these can be shift horizontally (by transforming inputs) or vertically (by transforming output), stretching (multiplying outputs or inputs) etc.

If the original function is y=f(x)A, assuming horizontal axis is input axis and vertical is for outputs, then:

  • Horizontal shift (also called phase shift):y=f(x+c)
  1. Left shift by c units: earlier)
  2. Right shift by c units: y=f(x-c) output, but c units late)
  • Vertical shift:
  1. Up by d units: y=f(x)+d
  2. Down by d units: y=f(x)-d
  • Stretching:
  1. Vertical stretch by a factor k: y=k\times f(x)
  2. Horizontal stretch by a factor k: y=f(\dfrac{x}{k})}

For this case, we're specified that:

y = cos(x) (the parent cosine function) was transformed to

y=0.35cos(8(x-\pi/4)

We can see its vertical stretch by 0.35, right shift by horizontal stretch by 1/8

Period of cos(x) is of  length. But 1.8 stretching makes its period shrink to

\dfrac{2\pi}{8}=\dfrac{\pi}{4}

Thus, the transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

vertical stretch of 0.35

horizontal compression to period of  (which means period of cosine is shrunk to  which originally was  )

phase shift of  to right

Learn more about transformation of functions here:

brainly.com/question/17006186

7 0
3 years ago
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