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3 years ago

Find the value of y, given that m<KLM = 135

Mathematics

2 answers:

dangina [55]3 years ago

4 0

Answer:

the value of y is, 5.5

Explanation:

GIven: $m\angle KLM=135^{\circ}$

Linear pairs is a pair of adjacent angles formed when two lines intersect.

In the figure, $m\angle kLN$ and $m\angle MLN$ forms a linear pair.

then, $m\angle KLM = m\angle KLN+m\angle MLN$ .

Substitute the values of $m\angle KLN= 47^{\circ}$ and $m\angle MLN= (16y)^{\circ}$ in above equation, to find the value of y;

⇒ $135^{\circ}=47^{\circ}+(16y)^{\circ}$ or

$16y^{\circ} =135^{\circ}-47^{\circ}$

Simplify:

$16y^{\circ} =88$

Divide 16 on both sides of an equation:

$\frac{16y}{16} =\frac{88}{16}$

Simplify:

$y=\frac{11}{2}$ or y=5.5

Therefore, the value of y = $\frac{11}{2}$ or y=5.5.

snow_tiger [21]3 years ago

3 0

I think this is right

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Step-by-step explanation:

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4 years ago

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jarptica [38.1K]

First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

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3 years ago

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun

AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

Nonsmokers Light Smoker Heavy smoker Total

Men 303 35 37 375

Women 413 31 45 489

Total 716 66 82 864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

$82C2=\frac{82!}{2!(82-2)!}=3321$

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

$864C2=\frac{864!}{2!(864-2)!}=372816$

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

$P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908$

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3 years ago