Assuming the lowest elevation is sea level and that the contour interval is 25 feet, approximately what elevation is point F
2 answers:
The given question is incomplete, as the attachment is missing which is as follows. According to the attachment provided the solution is as follows-Answer:
125 feet
Explanation:
In a topographic map, the elevations are shown with the help of contours, These are the lines of equal heights.
From the image, it is known that the contour interval is given to be 25 feet.
The outermost contour in the map is the mean sea level, where the elevation is 0 feet. Following inward the contour intervals increases by 25 feet. So it can be easily determined that-
The elevation at which location F lies is approximately at 125 feet above the mean sea level.
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The distance of the satellite form the earth is:
9,608,000 m (Option C) in Standard form, this is written as 9.6 x 10.
An Orbiting Satellite is a satellite that goes around the earth in an elliptical path known as an orbit.
To calculate the distance of the satellite from the earth we must equalize the force of Gravity to Centripetal Force given that these are the two forces that are at play here.
Step 1:
Equation that equalizes Gravity to Centripetality is:
G = mM/r² = m(v²/r)
Note that G = 6.67 x 10 (This is a gravitational constant.)
m is the Mass of the Satellite
M is Mass of the Earth
r is the distance of the satellite from the center of the earth
v is the satellites tangential velocity
Step 2 - Rearrange the formula and substitute the numbers above to get r
r = G (m/v²) = (6.67 x 10) (6 x10
/5000²) =
= 1.6 x 10m
Recall that form our postulation above, this is the satellites distance form the center of the earth.
To get it's distance form the earth's surface, we must know remove the value of the radius of the earth from the calculation. Where radius of the earth is given a r'
Hence,
r' = r - R = 1.6 x 10m - 6.4 x 10
m
= 9.6 x m or 9,608,000 m
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