F(x)= ∫ln²x/x dx= ∫ln²xd(lnx) cause d(lnx)= (lnx)'dx=1/x dx = ln³x/3 +C with C is constant In addition, we have f(2)=6, so we have 6=ln³2/3+C or C= 6- <span>ln³2/3 And f(x)= </span>ln³x/3+ <span> 6- </span><span>ln³2/3</span>
Sir your probably gunna report this but i have no equation if you could kindly provide the information I requested i would be happy to answer you question