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Sedaia [141]
3 years ago
12

You have a 12 foot ladder and need to reach exactly 9 feet up the wall. How far away from the wall should you place the ladder s

o that you can reach your desired location?
Mathematics
1 answer:
dusya [7]3 years ago
4 0
Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg

so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²

so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x

so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7

you should place it 3√7ft or about 7.9 or 8ft away

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Answer:

C. 5

Step-by-step explanation:

Use the Distance Formula.

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6 0
3 years ago
The measure of the two sides of a triangle. ​
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A.

Step-by-step explanation:

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7 0
3 years ago
Number one and number two
Amanda [17]
1.  sum of exterior angles = 360 

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B


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4 0
4 years ago
Find the Value of the letter in the following questions. Give your answers to 3 s.f.
Elis [28]

Answer:

i = 75.7°

h = 48.2°

Step-by-step explanation:

==>To find i, use the sine rule for finding angles: sin(A)/a = sin(B)/b

Where,

a = 7.2cm

sin(A) = i

b = 6.5cm

sin(B) = sin(61) = 0.8746

Thus:

sin(A)/7.2 = 0.8746/6.5

Multiply both sides by 7.2

sin(A) = (0.8746*7.2)/6.5

sin(A) = 0.969 (3 s.f)

A = i° = sin^-1(0.969) = 75.7 (3 s.f)

==>To find h, use the Cosine rule for angles:

Cos(C) = (a²+b²-c²)/2ab

cos(C) = h°, a = 4, b = 4.5, c = 3.5

a² = 16

b² = 20.25

c² = 12.25

cos(C) = (16+20.25-12.25)/(2*4*4.5)

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cos(C) = 0.667 (3 s.f)

C = h° = cos^-1(0.667) = 48.2° (3 s.f)

4 0
3 years ago
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