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Vesnalui [34]
3 years ago
11

A car moving at an initial velocity of 20 meters/second accelerates at the rate of 1.5 meters/second2 for 4 seconds. The car’s f

inal velocity is __meters/second.
Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0

v = v0 + at

= 20 + 1.5 × 4 m/s

= 20 + 6 m/s

=

26 m/s.

sineoko [7]3 years ago
4 0
The initial velocity: v o = 20 m/s.And :  a = 1.5 m / s² , t = 5 s.The final velocity formula:v = v o + a · tv = 20 + 1.5 · 5v = 20 + 7.5v = 27.5 m /sAnswer: The car`s final velocity is 27.5 meters / second.

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3 years ago
If the point A (6,9) is translated 4 units left, then find the new coordinates of the point A.
Alex_Xolod [135]

Answer:

(2, 9 )

Step-by-step explanation:

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3 years ago
Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day
likoan [24]

Answer:

Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = 5\frac34 \ hrs.

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

5\frac34 \ hrs. can be Rewritten as \frac{23}{4}\ hrs

Number of hours rode on first day = \frac{23}{4}\ hrs

Also Given:

Number of hours rode on second day = 6\frac45 \ hrs

6\frac45 \ hrs can be Rewritten as \frac{34}{5}\ hrs.

Number of hours rode on second day = \frac{34}{5}\ hrs.

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = 20-\frac{23}{4}-\frac{34}{5}

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = \frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day =\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.

Hence Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

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