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4 years ago

Consider the statement: “In a triangle, the measure of an

Mathematics

1 answer:

Lerok [7]4 years ago

5 0

Answer:

See the example given in the picture attached.

Step-by-step explanation:

No options are given, so I made my own example. In the picture attached, we can see that the measure of the exterior angle A is less than the measure of the adjacent interior angle B.

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It takes a baseball player 16 seconds to round the bases and make it back to home plate home plate if it is 360 feet to go all a

Neko [114]

S= D divided by T
S= 360 divided by 16
S= 22.5

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4 years ago

Please help me answer this question

julia-pushkina [17]

Answer:

Step-by-step explanation:

ten students are chosen from a statistics class of 300 let x be the number who got an a in the class

7 0

3 years ago

Solve y over negative 2 5 = 13.

devlian [24]

Y/-2 + 5 = 13
y/-2 = 13 - 5 = 8
y = -2(8) = -16
y = -16

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3 years ago

Read 2 more answers

1) A traditional die is a cube with each of its six sides representing the numbers from 1 to 6. Mr. Dicey customized a die by re

liraira [26]

Answer:

1) $\frac{2}{5}$

2) 49.225

3) $\frac{7}{2}$

Step-by-step explanation:

1) To find the expected value of the dice we can use the following equation:

$E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})$

So in our problem the values x will be: 1/1, 1/2, 1/3, 1/4, 1/5 and 1/6 and the probavility for all values is 1/6 so the expected values will be: $E(x)=(\frac{1}{1} *\frac{1}{6}) +(\frac{1}{2} *\frac{1}{6}) +(\frac{1}{3} *\frac{1}{6})+(\frac{1}{4} *\frac{1}{6})+(\frac{1}{5} *\frac{1}{6})+(\frac{1}{6} *\frac{1}{6})$

$E(x)=0.167+0.083+0.056+0.042+0.033+0.028=0.409\approx \frac{2}{5}$

2) To find the variance of the expected values we can use the equation:

$Var(x)=\frac{\sum_{i=1}^{n}(x_{i}-\overline{x})^{2} }{n}$

So for our problem will be:

$Var(x)=\frac{(3-10.5)^2+(4-10.5)^2+(17-10.5)^2+(18-10.5)^2}{4}$

$Var(x)=\frac{56.25+42.25+42.25+56.25}{4}$ $Var(x)=\frac{196.9}{4}=49.225$

3) To find the expected value of the dice we can use the following equation:

$E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})$

So in our problem the values x will be: 1, 2, 3, 4, 5 and 6 and the probavility for all values is 1/6 so the expected values will be: $E(x)=(1*\frac{1}{6}) +(2 *\frac{1}{6}) +(3 *\frac{1}{6})+(4 *\frac{1}{6})+(5 *\frac{1}{6})+(6 *\frac{1}{6})$

$E(x)=0.17+0.33+0.5+0.67+0.83+1=3.5\approx \frac{7}{2}$

7 0

3 years ago

Simplify: 3log3(-5) =

Illusion [34]

Answer:

Its D. undefined

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers