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Anni [7]
3 years ago
12

Consider the statement: “In a triangle, the measure of an

Mathematics
1 answer:
Lerok [7]3 years ago
5 0

Answer:

See the example given in the picture attached.

Step-by-step explanation:

No options are given, so I made my own example. In the picture attached, we can see that the measure of the exterior angle A is less than the measure of the adjacent interior angle B.

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Ugh ,, im stuck again :( someone please explain this !!!
EastWind [94]

Answer:

63cm²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle - Area of the two triangles

Area of the rectangle = 6(3+14)

Area of the rectangle = 6 * 17

Area of the rectangle = 102cm²

Area of the smaller triangle = 1/2 * 3 * 6

Area of the smaller triangle = 18/2 = 9cm²

Area of the larger triangle = 1/2 * 6 * (17-7)

Area of the larger triangle = 1/2 * 6 * 10

Area of the larger triangle = 60/2 = 30cm²

Area of the shaded part = 102 - (9+30)

Area of the shaded part = 102 - 39

Area of the shaded part = 63cm²

3 0
2 years ago
Shop Rite ordered 336 cases of Oreos with 42 packages in each case. What is the total number of Oreo packages that Shop Rite ord
Makovka662 [10]

Answer:

14112

Step-by-step explanation:

USE A CALCULATOR

4 0
3 years ago
Read 2 more answers
Check all of the ordered pairs that satisfy the equation below y equals 2 / 3 x
yanalaym [24]

Answer:

where are the ordered pairs

Step-by-step explanation:

5 0
2 years ago
(10v^4 + 30v^3 + 2v^2) / 10v
Zina [86]

Given expression is

\frac{10v^4+30v^3+2v^2}{10v}

Now we need to simplify this expression. We can begin by factoring numerator and denominator if possible.

= \frac{2v^2(5v^2+15v+1)}{10v}

divide numerator and denominator both by 2v

= \frac{v(5v^2+15v+1)}{5}

= \frac{5v^3+15v^2+1v}{5}

Hence final answer is \frac{5v^3+15v^2+1v}{5}

Or you can also keep factored form

\frac{v(5v^2+15v+1)}{5}

3 0
3 years ago
Look at the system of equations below<br> Sy= -2x +3<br> 1 4x – 3y = 11
kompoz [17]

Answer:

(2,-1)

y= -1

x= 2

Step-by-step explanation:

y= -2x+3

4x-3y=11

substitute the value of y into an equation

4x-3(-2x+3)=11

distribute by multiplying numbers in parenthesis by -3

4x+6x-9=11

add 4x to 6x

10x-9=11

add 9 from both sides

10x=20

divide both sides by 10

x=2

substitute the value of x into an equation

y= -2•2+3

multiply -2 to 2

y= -4+3

add -4 to 3 but 4 is negative, so subtract

y= -1

-----------

(2,-1)

-----------

3 0
2 years ago
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