<u>Answer-</u>
<em>The amount will be </em><em>$8944.62</em><em> after 5 years.</em>
<u>Solution-</u>
We know that,
![\text{FV of annuity}=P[\dfrac{(1+r)^n-1}{r}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3DP%5B%5Cdfrac%7B%281%2Br%29%5En-1%7D%7Br%7D%5D)
Where,
P = Payment = $50 monthly
r = rate of interest compounded monthly= ![3\frac{1}{4}=3.25\%=0.0325](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B4%7D%3D3.25%5C%25%3D0.0325)
n = number of period = 5 years = 5×12 = 60 months
Putting the values in the formula,
![\text{FV of annuity}=50[\dfrac{(1+0.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3D50%5B%5Cdfrac%7B%281%2B0.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{(1.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B%281.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{6.8140-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B6.8140-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{5.8140}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B5.8140%7D%7B0.0325%7D%5D)
![=50\times 178.8923](https://tex.z-dn.net/?f=%3D50%5Ctimes%20178.8923)
![=8944.62](https://tex.z-dn.net/?f=%3D8944.62)
Therefore, the amount will be $8944.62 after 5 years.
Let
![x](https://tex.z-dn.net/?f=x)
be the number of boxes the team brings with them. Their weight combined with the boxes can't exceed the capacity of 1400. Assuming the elevator runs fine at that exact weight, you want to find the number of boxes, each of which contributes 40 pounds. This is given by the equation
![1400=1200+40x](https://tex.z-dn.net/?f=1400%3D1200%2B40x)
Solving for
![x](https://tex.z-dn.net/?f=x)
, you have
![1400=1200-40x](https://tex.z-dn.net/?f=1400%3D1200-40x)
![200=40x](https://tex.z-dn.net/?f=200%3D40x)
![x=5](https://tex.z-dn.net/?f=x%3D5)
So the team can bring *at most* 5 boxes at a time.
<span>10.
if we were to
subsitute the points and graph the equation we would notice that the
shape is the same for both: a 45 degree angle line that goes upleft and
up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the
graph of y=|x|-4 is the same except that the graph is shifter 4 units
to the right ie. the point ofo the graph/rightangle is on point (4,0)
14.
slope intercept form which is y=mx+b
m=slope b=y intercept
m=4/3
y=4/3x+b
one given solution/point is (9,-1)
one solution is x=9 and y=-1 so subsitute and solve fo b
-1=4/3(9)+b
-1=36/3+b
-1=12+b
subtract 12 from both sides
-11=b
the equation si y=4/3x-11
see which one converts to the correct form
after trial and error we find that y-1=4/3(x-9) is the answer
</span>
That would be A :D It would be A because you would do keep change flip. You would keep 5/6, change the division sign to multiplication, then flip the 5/16 to 16/5 (the reciprocal)
start by writing the multiplication in this form
start multiplying from right to left.
![3\cdot0=0](https://tex.z-dn.net/?f=3%5Ccdot0%3D0)
write the first number down
continue by multiplying the next number from right to left
![8\cdot3=24](https://tex.z-dn.net/?f=8%5Ccdot3%3D24)
write the number down, since there are no more numbers to multiply for write the wole number
this means that