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gogolik [260]
3 years ago
13

Which type of drawer has three dispensing modes: single-dose, multi-dose, and matrix?

Computers and Technology
1 answer:
ad-work [718]3 years ago
6 0

Answer:

CUBIE MiniDrawer Bin

Explanation:

MiniDrawers comes in two configurations, and each fitting comes in one drawerslot. The MiniDrawer (1-6) comes with the most primary pocket dimensions. And we have the 18-tray MiniDrawer (1-8) comes with another dimensions in its basic form. You will in fact find various pocket dimensions like 1,2,3,4,6,12, and these comes within the 18-tray and 6-tray MiniDrawers. And they come in all the dispensing modes mentioned in the question. Hence, the above answer. The answer is clear from the options as well, and since it has the matrix mode as well apart from single dose mode and multi dose mode.

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Recover as much of the R-502 from the recovery unit as possible, change filter, and evacuate. In addition, to alter the compressor on a system containing R-410A, the person must isolate the compressor then evacuate the isolated section of the system to atmospheric pressure and hold. If system pressure does not increase, then remove the compressor. The recovered refrigerant may encompass acids, moisture and oils and every air conditioning or refrigerating system should be secure by a pressure relief device. 
5 0
3 years ago
Jeff gave a presentation that attempted to convince stockholders to purchase the new software he had developed. What type of pre
Travka [436]

Answer: Progress report presentation

Explanation: Progress report presentation is the presentation that consist the progress report of an individual's work .It describes about the project/work that a person has started to complete the project. These reports are made for the clients, students, colleagues etc.

Progress report in this case is made for the client to make them understand about the Jeff's work , his contribution, changes he invoked in it, achievements ,completion of the project, benefits of it etc. This presentation will encourage the client to buy the software made by Jeff.

7 0
4 years ago
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Ede4ka [16]

Answer:

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Explanation:

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4 0
3 years ago
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Write a program to simulate the design process of the course. First, create a struct for the course which consists of following
Dmitry [639]

Answer:

#include <iostream>

using namespace std;

struct Course

{

int courseNumber;

int courseStartDate;

int courseHours;

int lecturerId;

};

struct Lecturer

{

int lecturerId;

int officeHours;

Course courseTeaching[2];

};

struct Student

{

int studentId;

Course coursesTaken[2];

};

int main()

{

Course courseObj1, courseObj2, courseObj3;

courseObj1.courseNumber = 1000;

courseObj1.courseStartDate = 20200107;

courseObj1.courseHours = 2;

courseObj1.lecturerId = 100;

courseObj2.courseNumber = 1100;  

courseObj2.courseStartDate = 20200113;

courseObj2.courseHours = 4;

courseObj2.lecturerId = 200;

courseObj3.courseNumber = 1200;

courseObj3.courseStartDate = 20200203;

courseObj3.courseHours = 4;

courseObj3.lecturerId = 100;

Lecturer lecturerObj1, lecturerObj2;

lecturerObj1.lecturerId = 100;

lecturerObj1.officeHours = 2;

lecturerObj1.courseTeaching[0] = courseObj1;

lecturerObj1.courseTeaching[1] = courseObj3;

lecturerObj2.lecturerId = 200;

lecturerObj2.officeHours = 2;

lecturerObj2.courseTeaching[0] = courseObj2;

Student student;

student.studentId = 2000;

student.coursesTaken[0] = courseObj1;

student.coursesTaken[1] = courseObj3;

cout << "1. Lecturer ID: " << lecturerObj1.lecturerId << "\tOffice Hours: " << lecturerObj1.officeHours << endl;

for(int i = 0; i < 2; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj1.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj1.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj1.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj1.courseTeaching[i].lecturerId << endl;

cout << "\n2. Lecturer ID: " << lecturerObj2.lecturerId << "\tOffice Hours: " << lecturerObj2.officeHours << endl;

for(int i = 0; i < 1; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj2.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj2.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj2.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj2.courseTeaching[i].lecturerId << endl;

int courseNumber;

cout << "\n Enter the course number: ";

cin >> courseNumber;

int index = -1;

int len = sizeof(student.coursesTaken) / sizeof(student.coursesTaken[0]);

int totalHours = 0;

for(int i = 0; i < len; i++)

{

if(student.coursesTaken[i].courseNumber == courseNumber)

{

totalHours += student.coursesTaken[i].courseHours;

}

}

if(totalHours == 0)

cout << "\n Student is not registered to this course!\n";

else

cout << "\nStudent " << student.studentId << " needs " << totalHours << " hours per week of this course.\n";

return 0;

}

Explanation:

  • Create the 3 objects of Course class and set their properties respectively.
  • Create the 2 objects of Lecturer class and set their properties respectively.
  • Create an object of Student class and set their properties respectively.
  • Run a for loop and check whether the current courseNumber is already added and then increment the total number of hours for that course.
  • Finally check if totalHours is equal to 0 or not and then display the suitable message accordingly.
4 0
4 years ago
What will be the value of ans after the following code has been executed?
Lesechka [4]

Answer:

Option B 120

Explanation:

There are three variables,<em> ans, x </em>and <em>y</em> given in the code. In beginning, the variable. <em>ans,</em> holds value of 10.  And variable <em>x</em> and <em>y</em> hold value of 65 and 55, respectively. Since the value held by x is bigger than one held by y, the if condition is met and the statement ans = x + y will run. The execution of this statement will total x with y -> 65 + 55 and the initial value of <em>ans is </em>overwritten by the addition result which is 120.

7 0
3 years ago
Read 2 more answers
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