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KengaRu [80]
3 years ago
7

Kali is single and earns $45,800 per year. What is her annual federal withholding?

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

90,000

Step-by-step explanation:

this is wrong

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F (x) = 2x^2 - 4x + 1
Kobotan [32]

Answer:

<h2><u>tinanong ko rin po yang tanong nyo at ito po ang sagot nila</u></h2>

3 0
2 years ago
Haily paid $13 for 1 and 3/7 kf of sliced salami. What was the cost per kilogram of salami?
nikdorinn [45]

13 divided by 1 and 3/7=9 and 1/10

$9.10

4 0
3 years ago
What is the average of 4 1/2, 3 1/3, 2, 2 1/6? I will give brainleist.
kotykmax [81]

Answer:

3

Step-by-step explanation:

  4 1/2 + 3 1/3 + 2 + 2 1/6

= 4 3/6 + 3 2/6 + 2 + 2 1/6

= 4 + 3 + 2 + 2 + 3/6 + 2/6 + 1/6

= 11 + 6/6

= 11 + 1

= 12

There are 4 numbers, therefore average = 12 ÷ 4 = 3

7 0
2 years ago
A country's population in 1991 was 147 million. In 1998 it was 153 million. Estimate the population in 2017 using the exponentia
Aloiza [94]
K = ln (153/147)/7
k = <span> ln (<span> <span> 1.0408163265)/7
k = </span></span></span>0.040005334584

y(t) = a * e ^ k*t

y(2017) = 147 * e^ <span><span><span>0.040005334584 </span> </span> </span> * 26
y(2017) = 147*e^ <span> <span> <span> 1.0401386992 </span> </span> </span>
y(2017) = 147* <span> <span> <span> 2.8296094512 </span> </span> </span>
<span>y(2017) = 415.95 NOT very sure of that answer


</span>









6 0
3 years ago
Please help me ! Reduced to lowest terms
Mandarinka [93]

Answer:

Step-by-step explanation:

7) 2ab + 4ac = 2*a*b + 2 *2 *a*c

                     = 2a(b + 2c)

\dfrac{2ab^{2}c}{2ab+4ac}=\dfrac{2*a* b^{2}*c}{2a(b+2c)}\\\\\\\text{2a in the denominator and numerator get cancelled}\\\\ = \dfrac{b^{2}c}{b+2c}

8) ac - a²c² = c( a - a²c)

bc - abc     = c(b - ab)

\dfrac{ac - a^{2}c^{2}}{bc-abc^{2}}=\dfrac{c(a-a^{2}c)}{c(b-ab)}\\\\

               =\dfrac{a-a^{2}c}{b-abc}

9) b²+ 4b - 5 = b² + 5b - 1b - 5

                    = b(b + 5) - 1(b + 5)

                    = (b +5)(b - 1)

b² + 8b  + 15 = b² + 5b + 3b + 15

                    = b(b + 5) + 3(b + 5)

                    = (b + 5 )(b + 3)

\dfrac{b^{2}+4b-5}{b^{2}+8b+15}=\dfrac{(b+5)(b-1)}{(b+5)(b+3)}\\\\\\

                     =\dfrac{b-1}{b+3}

8 0
2 years ago
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