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3 years ago

8

A microchip can process 1,280 bits of information in 3.2 x 10 (exponent) -7 seconds. How many bits of information could it proce

ss in one hour

1 answer:

Elena L [17]3 years ago

5 0

3600 seconds/hour, 3600/3.2x10^-7= (11250000000)(1,280)= 1.44e+13

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Please help me also explain your answer so I can get better at this thank you :)

Elina [12.6K]

Answer: 880

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2 years ago

Read 2 more answers

Can someone help me with this question?

Masteriza [31]

Answer:

V=2c

Step-by-step explanation:

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2 years ago

Alenkinab [10]

Option a) is the right answer

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3 years ago

Solve the following proportion4 x— = —7 28x=

Ierofanga [76]

Answer:

x = 16

Explanations:

The given rquation is:

$\frac{4}{7}=\text{ }\frac{x}{28}$

Step 1: Cross multiply the equations. That is 28 multiplies 4 and 7 multiplies x:

$28\text{ x 4 = 7 }\times\text{ x}$ 112 = 7x

Step 2: Divide both sides by 7

$\frac{112}{7}=\text{ }\frac{7x}{7}$ 16 = x x = 16

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1 year ago

a psychologist contends that the number of facts of a certain type that are remembered after t hours is given by the following f

laiz [17]

Answer:

At t=1, Rate of Change=-36.86

At t=10 hours, Rate of Change =-0.0088

Step-by-step explanation:

The function which describes the number of facts of a certain type which are remembered after t hours is given as:

$f(t)=\frac{85t}{99t-85}$

To determine the Rate of Change at the given time, we first look for the derivative of f(t).

Applying quotient rule:

$f^{'}(t)=\frac{-7225}{{\left( 85 - 99\,t\right) }^{2}}$

At t=1

$f^{'}(1)=\frac{-7225}{(85-99)^{2}}$

=-36.86

At t=10 hours

$f^{'}(10)=\frac{-7225}{(85-99(10))^{2}}$

=-0.0088

4 0

3 years ago