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lara31 [8.8K]
4 years ago
13

My answer is A! I’m right or no!

Mathematics
1 answer:
amid [387]4 years ago
5 0
No it is b 

hope I helped !:)
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Savatey [412]
Number 1 76
number 2 760,000
number 3 760
8 0
3 years ago
Solve and explain for brainliest
natima [27]
6.32 units squared
a^2+b^2=c^2
3^2+b^2=7^2
9+ b^2= 49
-9. -9
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4 0
3 years ago
In parallelogram ABCD , diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E, BE=2x2−x , and DE=x2+6 .
kondaur [170]
<span>The diagonals of a parallelogram bisect each other. So we just equate the two equations BE and DE 2x^2 - x = x^2 + 6 2x^2 - x - x^2 - 6 = 0 x^2 - x - 6 = 0 This is quadratic eqn. So we obtain. (x - 3) ( x + 2) = 0 Setting each to 0 and solving for x, we have that x = 3 and x = -2 So we have two possible values for BD. But Since BE = DE then we can simply double each If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
8 0
3 years ago
Read 2 more answers
Any help to solve this problem. Provide steps. Thnx
Alekssandra [29.7K]

Answer:

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.

the area of the rectangle is 150cm^2.

now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

22 - 15 = 7.

now we know that the height of the triangle is 7 cm.

from earlier, we also know the base, which is 10cm.

7 x 10 = 70cm^2.

now we add all these together:

70 + 150 + 64 = 284cm^2

8 0
3 years ago
Read 2 more answers
How do I do this im having trouble and its my exam day?
Gnom [1K]

Answer:

C.

Step-by-step explanation:

So basically set (10x-13) equal to (3x+22) and then solve for x

x=5

Plug 5 into the equations

(10(5)-13)=37

(3(5)+22)=37

These two angles are congruent due to the triangle being isosceles

37+37=74

All angles in a triangle are equal to 180 degrees

Therefore 180-74=106

Angle JKL= 106 degrees

Hope this helps :)

6 0
4 years ago
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