All categories

3 years ago

Can someone please help me

1 answer:

4 0

Using exponentials, the expression can be presented as the following:

= 7^(1/3) * 7^(1/2) / 7^(1/6)= 7^(1/3 + 1/2 - 1/6)= 7^(2/6 + 3/6 - 1/6)= 7^(2/3)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

You might be interested in

The table shows how much an air-conditioning repair company charges for different numbers of hours of work. Write the equation i

Sloan [31]

Answer:

x over y using the numbers given

Step-by-step explanation:

5 0

3 years ago

Specialty tshirts are being sold for $30.........

kaheart [24]

Equal out the shirts so that u can know what U are doing

3 0

3 years ago

Carl went to the store to buy items for his party.He bought two packs for plates for $3.24 and a pack of cups for $5.70. He also

Andre45 [30]

3.24 + 5.70 + 6.17 = 15.11

20.00 - 15.11 = 5.11

He got 5.11$ of change back.

7 0

3 years ago

18 What is the value of y? 10 2y + 4 10 + 2x 5

vredina [299]

Answer:

i got 4 but idk if its roght srry give it an try

5 0

3 years ago

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let x be the width and y the length of the rectangular field.

Let C the total cost of the rectangular field.

The side made of heavy duty material of length of x costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are x, y, y. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

3 years ago