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Anastasy [175]
3 years ago
5

When Mrs Jay split her class into groups of four, there were two children left over. When she split them into groups of five, th

ere was one child left.
How many children were there in the class?
Mathematics
1 answer:
wlad13 [49]3 years ago
7 0
21 kids were in the class.

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Ronnie, Mack, Kim, and Ada together stacked a total of 40 pizzas in a pan. Ronnie stacked 0.25 of the pizzas, Mack stacked 9 of
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Hello!

Here's how much each person stacked:

Ronnie -- 0.25 of the 40 pizzas.

Mack -- 9/40

Kim -- 35% of the 40 pizzas.

Ada -- rest of the pizzas.

Now, the questions asks for who stacked the most pizzas.

First, find our how many pizzas they stacked out of 40.

40 × 0.25 = 10

40 × 35% = 14

10 + 9 + 14 = 33

40 - 33 = 7

This means that Ronnie stacked 10 pizzas, Mack stacked 9 pizzas, Kim stacked 14 pizzas, and Ada stacked 7 pizzas.

ANSWER:

Kim stacked the most pizzas since she stacked 14 of them.
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3 years ago
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It would be a profit  of .35 cents

Step-by-step explanation:

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How do you determine if a given set of measurements works for the side lengths of a triangle? (It should be a number)
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Add them all up and if they add up to 180 then your side lengths are good
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4 years ago
Please solve the whole page
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1. 3/20    

2. 76/4

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2 years ago
Express the confidence interval 0.333less thanpless than0.555 in the form ModifyingAbove p with caret plus or minus Upper E. Mod
elena-14-01-66 [18.8K]

Answer:

The confidence interval is (0.444 ± 0.111).

Step-by-step explanation:

The general form of a confidence interval for single proportion is: (\hat p- E

The interval provided is: (0.333 < p < 0.555)

Then

\hat p-E=0.333...(i)\\\hat p + E = 0.555...(ii)

Solving the two equation simultaneously:

Add (i) and (ii),

2\hat p=0.888\\\hat p=\frac{0.888}{2}\\ =0.444

Substitute the value of \hat p in (i) to compute the value of <em>E:</em>

\hat p-E=0.333\\0.444-E=0.333\\E=0.444-0.333\\=0.111

Thus, the confidence interval is,

(0.444-0.111

7 0
3 years ago
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