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2 years ago

Trapezoid with congruent legs and congruent bases are?

Mathematics

2 answers:

TiliK225 [7]2 years ago

6 0

By most definitions, if the bases are congruent, it is not a trapezoid, it is a parallelogram.

solong [7]2 years ago

5 0

I'm not positive that this is correct but It might be a quaderalateral.

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Let f(x)=ln(3x)+2.5 .

Cerrena [4.2K]

For this case what we should do is evaluate the function in each of the points from 2 to 7 and then find the average.
We have then:
f (x) = ln (3x) +2.5.
f (2) = ln (3 * 2) + 2.5 = 4.291759469
f (3) = ln (3 * 3) + 2.5 = 4.697224577
f (4) = ln (3 * 4) + 2.5 = 4.98490665
f (5) = ln (3 * 5) + 2.5 = 5.208050201
f (6) = ln (3 * 6) + 2.5 = 5.390371758
f (7) = ln (3 * 7) + 2.5 = 5.544522438
Then the average is:
Average = (4.291759469 + 4.697224577 + 4.98490665 + 5.208050201 + 5.390371758 + 5.544522438) / (6) = 5.019472516
nearest hundredth
5.02
Answer:
the average rate of change of f (x) from 2 to 7 is 5.02

5 0

3 years ago

Read 2 more answers

After flying between two black holes, our engines have been a bit janky. The probability of one of any of our 8 power couplings

otez555 [7]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution. It is expressed as

P(x = r) = nCr × q^(n - r) × p^r

Where

p represents probability of success

q represents probability of failure.

n represents number of sample.

From the information given,

p = 10% = 10/100 = 0.1

q = 1 - q = 1 - 0.1 = 0.9

n = 8

1)The probability that none fails is

P(x = 0) = 8C0 × 0.9^(8 - 0) × 0.1^0

P(x = 0) = 0.43

2) The probability that one fails is

P(x = 1) = 8C1 × 0.9^(8 - 1) × 0.1^1

P(x = 1) = 0.38

3) The probability that four fails is

P(x = 4) = 8C4 × 0.9^(8 - 4) × 0.1^4

P(x = 4) = 0.0046

3) The probability that six fails is

P(x = 6) = 8C6 × 0.9^(8 - 6) × 0.1^6

P(x = 6) = 0.00002268

4) The probability that eight fails is

P(x = 8) = 8C8 × 0.1^(8 - 8) × 0.1^8

P(x = 8) = 0.00000001

5 0

3 years ago

Which of these is a simplified form of the equation 8y + 4 = 6 + 2y + 1y?

larisa86 [58]

The first one would be the right one!

you just take all the y one side and the numbers on one side
so 8y+4= 6+3y

now 8y-3y= 6-4

therefore 5y = 2

!!

3 0

3 years ago

Read 2 more answers

Simplify (4y - 3x - 2) - (7y + 4x + 3)

yarga [219]

Answer:

-7x - 3y -5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n

irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0

3 years ago