To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
The figure consists of a triangle and two rectangles.
-----------------------------
Top Triangle:
-----------------------------
Height = 22 - 10 - 7 = 5cm
Base = 20 - 5 - 5 - 10cm
Area of triangle = 1/2 x 5 x 10 = 25 cm²
-----------------------------
Middle Rectangle:
-----------------------------
Length = 10cm
Width = 7cm
Area = 10 x 7 = 70 cm²
-----------------------------
Bottom Rectangle:
-----------------------------
Length = 20 cm
Width = 10 cm
Area = 20 x 10 = 200 cm²
-----------------------------
Total Area:
-----------------------------
Area = 25 + 70 + 200 = 295 cm²
-----------------------------
Answer: Area = 295 cm²
-----------------------------
Answer:
Step-by-step explanation:
a)
the sum of all angles in a quadrilateral must be 360º
y+88+25+35 = 360
y = 360=88-25-35
y = 212º
b)
the sum of all angles in an octagon must be 1080º
45+45+140+140+6y = 1080
6y = 1080-90-280
6y = 710
y = 710/6
y=~ 118,3º
Answer:
should be either b or c
Step-by-step explanation:
ee ni mee ni my nee mo
Y can be any number with the given question
