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alekssr [168]
4 years ago
7

Given r= 10 and e=0.57, find the Cartesian coordinates. Check your answer.

Mathematics
1 answer:
Rudik [331]4 years ago
3 0
I think it is d not sure tho
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
hodyreva [135]

Answer:

If two variables are directly proportional, it means that an increase in the value of one variable would cause a corresponding increase in the other variable. If they are inversely proportional, an increase in the value of one variable would cause a corresponding decrease in the other variable.

Looking at the given values, as x is increasing, y is also increasing. The constant of proportionality is

9/3 = 27/9 = 3

Therefore, the relationship is a direct variation and the function to model it is

y = 3x

Step-by-step explanation:

3 0
2 years ago
X^2+y^2-4y-15=6
myrzilka [38]

Answer:

x^2 + y^2 - 4y - 15 = 6

x^2 + y^2 - 4y = 21

x^2 + y^2 - 4y + 4 = 25

x^2 + (y - 2)^2 = 5^2

r = 5

8 0
3 years ago
WILL MARK BRAINLIEST IF ITS RIGHT !!
Furkat [3]

Answer:

Around 0.22

<u>FIRST THOUGH, I FEEL LIKE 90 MIGHT HAVE MEANT TO BEEN 0.9, SO IF SO SUBSTITUTE THE 90 BELOW FOR 0.9!</u>

<u></u>

Step-by-step explanation:

Okay, so first.

Company A will be 50 a day plus 0.4 a mile

Company B will be 30 a day plus 90 per mile

We can write an equation like this:

50 + 0.4m = 30 + 90m

m = miles they are the same

Then we solve for m.

50 + 0.4m = 30 + 90m

     - 0.4m            - 0.4m

50 = 30 + 89.6m

- 30    - 30

20 = 89.6m

Divide both sides by 89.6

Around 0.22!

5 0
3 years ago
Solve for the variable in 6⁄18 = x⁄36 A. 12 B. 6 C. 3 D. 9
RoseWind [281]
\dfrac{6}{18}  = \dfrac{x}{36} 

\dfrac{1}{3} =  \dfrac{x}{36} 

\dfrac{1}{3} * 36 = x   |Multiply \ by \ 36|

x= \dfrac{36}{3}  |Divide \ both \ sides \ by \ 3|

x=12
4 0
3 years ago
If [x] denotes the least integer greater than or equal to x and [x/2] = 0, which of the following could be the value of x?A. -2B
podryga [215]

Answer:

B) -3/2

Step-by-step explanation:

If [x/2]=0 then x/2 is a number such that the least integer greater than or equal to x/2 is 0. We can rewrite this as the inequality x/2≤0. Then, the value of x in C, D and E is wrong because they are positive numbers, then x/2 would be a positive number which contradicts this inequality.

Now, 0 is the least integer that satisfies this inequality, therefore we cannot have that x/2≤-1 since -1 is an integer and -1<0. Then x/2>-1. This discards A as wrong, because for x=-2, x/2=-1, contrary to x/2>-1.

Thus B is the right answer. To verify, if x=-3/2, then x/2=-3/4 and we have that -1<-3/4≤0 as required.

3 0
3 years ago
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