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4 years ago

A ray cannot be divided into two congruent segments. True or false?

Mathematics

2 answers:

Dmitrij [34]4 years ago

7 0

i think its true because i put it in a test answer and go it right

Blababa [14]4 years ago

3 0

The answer would be false.

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Show all work to factor x^4 − 10x^2 + 9 completely.

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x²-y² formula

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2 years ago

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

amm1812

Answer:

Given:

Sham: n= 20, x=0.44, s=1.24,

Magnet:n= 20, x =0.49, s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

$\frac{s1^2}{s2^2}$

$\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037$

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom $= n - 1 = 20 - 1 = 19$

Magnet: degrees of freedom $= n - 1 = 20 - 1 = 19$

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

$f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]$

$f[0.025, 19, 19], f[0.975, 19, 19]$

$(2.526, 0.3958)$

The rejection region:

Reject H0, if F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0

3 years ago

What number is 44% of 25

AysviL [449]

44 percent of 25 is 11 to get percentage u would take 44 and divide it by a hundred and u would get .44 and then u would multiply that by 25 and u get 11

8 0

3 years ago

Read 2 more answers

f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many

Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: