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Dmitrij [34]
3 years ago
15

If x=100 what is x squared divided by 2

Mathematics
2 answers:
artcher [175]3 years ago
8 0
500 because 100 times 100=1,000
1,000/2=500
posledela3 years ago
7 0
100 divided by 2 equals to 50
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2x + (-x) + 3 + (-2)
meriva

Answer:

-x+3

Step-by-step explanation:

hope this helps

4 0
3 years ago
Solve for x<br><br> -1/5 + 5 = -5<br><br> A. 10<br> B. -10<br> C. 50<br> D. -50
hammer [34]

Answer:

t=50 so C

Step-by-step explanation:

multiply both sides by 5

-t=-25-25

-t=-50

divide by -1

t=50

where u get t=50

3 0
3 years ago
When should you use graphing to solve a system?
nignag [31]
Yes you should. When using a system
4 0
3 years ago
Read 2 more answers
The town of madison has a population of 25,000. The population is increasing by a factor of 1.12 each year. Write a function tha
GaryK [48]
<h3>The population P(t) at the end of year t is   P(t)   = 25,000 \times (1.12)^t</h3>

Step-by-step explanation:

The initial population of town of Madison = 25,000

The rate at which the population is increasing = 1.12 times

So, the increase in population first year  :

( the initial population)  x (1.12)^1  = 1.12 x ( 25,000)  

= 28,000

So, the population at the end of first year = 28,000

Similarly, the increase in population second year  :

( the initial population)  x (1.12)²  =  ( 25,000)   x (1.12)²

= 31,360

So, the population at the end of second year =31,360

Now, to calculate the population in t years from now:

The population P(t) at the end of year t is

P(t)   = 25,000 \times (1.12)^t

5 0
3 years ago
If x/0.5 + y/0.2 = 18, where x and y are positive integers, then what is the value of x ?
dem82 [27]
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.

Let's see where the line crosses the x-axis, it is where y=0:

x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).

Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.

You will find that x=4, y=2 is the only pair that satisfies these conditions.

7 0
3 years ago
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