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Nat2105 [25]
3 years ago
9

PLEASE HELP whats 5/8 times 4/7

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0
5/8 times 4/7 is 5/14
blsea [12.9K]3 years ago
5 0
5/8 times 4/7 is 5/14.
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What is the range of the relation?
Westkost [7]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
Which equation can be used to find the volume of this solid?
bogdanovich [222]

Answer:

V= 2 times 4 times 5

Step-by-step explanation:

In order to calculate the volume of a figure u must calculate lwh or length times width times height. In this case length is 5 width is 4 and height is 2. This can be plugged in and becomes 2 times 4 times 5.

6 0
3 years ago
Read 2 more answers
Describe the transformations of how the graph y=x^2 can be transformed into y= -1/5 (x-4)^2 + 2
Orlov [11]

Answer:

Reflected over the x-axis, vertically shrunk by a factor of 1/5, moved right 4 units and up 2 units.

Step-by-step explanation:

Parent Graph: f(x) = a(bx - h)² + k

<em>a </em>is vertical stretch (a > 1) or shrink (a < 1) and reflection over x-axis

<em>b</em> is horizontal stretch or shrink and reflection over y-axis

<em>h</em> is horizontal movement left (if positive) or right (if negative)

<em>k</em> is vertical movement up (if positive) or down (if negative)

Now that we have our rules, we simply apply it to y = -1/5(x - 4)² + 2

<em>a</em> = -1/5, so reflection over x-axis and vertical shrink of 1/5 (1/5 < 1)

Nothing has changed <em>b</em>, so no horizontal stretch/shrink

<em>h</em> = -4, so horizontal movement right 4 units

<em>k</em> = 2, so vertical movement up 2 units

8 0
3 years ago
The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis
Firdavs [7]

Answer:

sin\theta_1 =  - \frac{2\sqrt{70}}{19}

Step-by-step explanation:

We are given that \theta_1 is in <em>fourth</em> quadrant.

cos\theta_1 is always positive in 4th quadrant and  

sin\theta_1 is always negative in 4th quadrant.

Also, we know the following identity about sin\theta and cos\theta:

sin^2\theta + cos^2\theta = 1

Using \theta_1 in place of \theta:

sin^2\theta_1 + cos^2\theta_1 = 1

We are given that cos\theta_1 = \frac{9}{19}

\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{280}{361}\\\Rightarrow sin\theta_1 =  \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 =  +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}

\theta_1 is in <em>4th quadrant </em>so sin\theta_1 is negative.

So, value of sin\theta_1 =  - \frac{2\sqrt{70}}{19}

6 0
3 years ago
Which of the following correctly shows the re-grouping for 45 x 12? Group of answer choices 40 x 10; 5 x 10; 40 x 2; 5 x 40
Damm [24]

Answer:

40x10;5x10;40x2;5x2

400+50+80+10

=540

5 0
3 years ago
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