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3 years ago

Find the product. (3x + y) (3x - 3y)

Mathematics

2 answers:

Katarina [22]3 years ago

7 0

Answer:

$9x^{2} -6xy-3y^{2}$

Step-by-step explanation:

$(3x+y)(3x+-3y)$

$(3x)(3x)+(3x)(-3y)+(y)(3x)+(y)(-3y)$

$9x^{2} -9xy+3xy-3y^{2}$

$9x^{2} -6xy-3y^{2}$

daser333 [38]3 years ago

5 0

Answer:

9xsq - 6xy -3ysq

Step-by-step explanation:

3x x 3x = 9xsq

3x x -3y= -9xy

y x 3x = 3xy

y x -3y= -3ysq

9xsq -9xy +3xy -3ysq

9xsq -6xy - 3ysq

sq = squared

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Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.

WARRIOR [948]

The polynomial $2x^3 + 5x^2-8x-20$ may have solutions which are the divisors of -20, therefore -20 has the following divisors: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .
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Since x-2 and x+2 are two factors of $2x^3 + 5x^2-8x-20$ , then the polynomial $x^2-4$ is a divisor of $2x^3 + 5x^2-8x-20$ and dividing the polynomial $2x^3 + 5x^2-8x-20$ by $x^2-4$ you obtain
$2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5)$ .

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Solve the inequality and graph the solution -5-7x < -40

Elza [17]

Answer:

x > 5

Step-by-step explanation:

-5-7x < -40

Add 5 to each side

-5+5-7x < -40+5

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Divide by -7, remembering to flip the inequality

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