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3 years ago

6th grade math , help me please :)

Mathematics

1 answer:

Damm [24]3 years ago

6 0

Answer:

a= 7/20

b=35

Step-by-step explanation:

A was simple because 7 people with blue eyes for every 20 people written in fraction form. For b they say what if it was 100 total people so 20 x 5 = 100 so 7 x 5= 35 so your answer to b is 35

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Problem 7-35 A satellite range prediction error has the standard normal distribution with mean 0 NM and standard deviation 1 NM.

hammer [34]

Answer:

Kindly check explanation

Step-by-step explanation:

For a normal distribution with :

Mean(m) = 0

Standard deviation (s) = 1

Calculate :

(a) less than 1.17 NM Probability

Zscore = (x - m) / s = (1.17 - 0) / 1 = 1.17

P(z < 1.17) = 0.879

(b) between 1.04 NM and 1.99 NM Probability

Zscore = (x - m) / s = (1.04 - 0) / 1 = 1.04

P(z < 1.04) = 0.8508

Zscore = (x - m) / s = (1.99 - 0) / 1 = 1.99

P(z < 1.99) = 0.9767

(0.9767 - 0.8508) = 0.1259

P(Z > 0.93) = 1 - p(Z < 0.93) = 1 - 0.8238 = 0.1762

(d) between 0.24 NM and 0.73 NM Probability

P(Z < 0.24) = 0.5948

P(Z <0.73) = 0.7673

0.7673 - 0.5948 = 0.1725

(e) less than or equal to 2.3 NM Probability

P(Z ≤ 2.3) = 0.9893

(f) greater than 2.22 NM or less than .65 NM

P(Z > 2.22) = 1 - p(Z < 2.22) = 1 - 0.9868 = 0.0132

P(Z < 0.65) = 0.7422

0.7422 - 0.0132 = 0.729

(g) greater than or equal to 2.0 NM Probability

P(Z ≥2) = 1 - p(Z ≤ 2)

1 - 0.97725 = 0.02275

3 0

3 years ago

I am not quite sure how to do these.

EleoNora [17]

Sin (Π/2 - theta) = sin(Π/2) * cos(theta) - cos(Π/2) * sin (theta)
and as we know sin(Π/2) =1 , cos(Π/2)=0
so sin(Π/2 - theta) = 1* cos(theta) - 0* sin(theta)= cos(theta)
2nd cos(180+ theta) = cos(180)*cos(theta) - sin(180)* sin(theta)
,,, so , cos(180+theta) = -cos(theta)

6 0

4 years ago

Which of the following is the equation for x: ax^2=bx? select all that apply please help

Vadim26 [7]

the answer to your question is x = b/a and x = 0

7 0

4 years ago

Simplify radicals problems attached please help!

Finger [1]

Answer:

G7. (2√3)/3

G8. -2+√7

G9. (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

$\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}$

G8.

$\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2$

G9.

$\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}$

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0

4 years ago

20-x=6. Explain how you would solve the equation

MaRussiya [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

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