The volume as a function of the location of that vertex is
... v(x, y, z) = x·y·z = x·y·(100-x²-y²)
This function is symmetrical in x and y, so will be a maximum when x=y. That is, you wish to maximize the function
... v(x) = x²(100 -2x²) = 2x²(50-x²)
This is a quadratic in x² that has zeros at x²=0 and x²=50. It will have a maximum halfway between those zeros, at x²=25. That maximum volume is
... v(5) = 2·25·(50-25) = 1250
The maximum volume of the box is 1250 cubic units.
Answer:
Step-by-step explanation:
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Answer:
<UOX and <YOZ
Step-by-step explanation:
Adjacent angles are angles that share a common side and vertex. So, find the angles that share one side. In this case, the two sides of the angle <XOY are OX and YO. Remember when naming an angle that it should be one side, the vertex, the last side. So, the 2 adjacent angles are <UOX and <YOZ because they each share one common side and vertex.
Answer:
P = 7
Step-by-step explanation:
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Answer:
Step-by-step explanation:
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