A piece of paper is randomly selected from a stack that contains 15 small, 44 large, and 20 extra large pieces.

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

59% of 640. We are supposed to find the percent of each number (as you can see)

Novosadov [1.4K]

Answer:

377.6

Step-by-step explanation:

Multiply 59 by 640 and then move the decimal point over two numbers.

59% of 640

59 x 640

37760.0

377.6

4 0

3 years ago

The power generation plant of a ship is outfitted with two identical diesel-generator sets. One single set running stand-alone c

dem82 [27]

Answer:

probability of an electric power outage shipboard is 0.075 or 7.5 %

Step-by-step explanation:

Given the data in the question;

Probability of engine malfunction = 25% = 0.25

Probability of generator malfunction = 10% = 0.1

Probability of generator being repaired = 50% = 0.5

probability of an electric power outage shipboard = ?

To get the probability of an electric power outage shipboard, we use the expression;

probability of an electric power outage = 2 $_c_1$ × p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )

so we substitute in our given values;

probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )

probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75

probability of an electric power outage = 0.075 or 7.5 %

3 0

3 years ago

Find the average of these numbers. 23, 24, 27, 25, 26, 23, 21, 32, 29, 30

Pavel [41]

Answer:

26

Step-by-step explanation:

First, add all the numbers together

23 + 24 + 27 + 25 + 26 + 23 + 21+ 32 + 29 + 30= 260

Then divide by the number of terms there are, in this case 10

260/10= 26

6 0

3 years ago

Read 2 more answers

Is that correct ????

Travka [436]

Yes I believe it is :)

7 0

3 years ago