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4 years ago

PLEASE HELP HELP HELP HELP HELP HELP

Mathematics

1 answer:

RideAnS [48]4 years ago

7 0

$|\Omega|=12\cdot11\cdot10=1320\\|A|=9\cdot8\cdot7=504\\\\P(A)=\dfrac{504}{1320}=\dfrac{21}{55}\approx38.2\%$

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Find the selling price of a $36 item after a 50% markup

agasfer [191]

Answer:

$54

Step-by-step explanation:

36 divided by 2= 18

$36+$18=$54

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2 years ago

Question 5<br>(a) Complete the square for x2 - 10x + 3.<br>(b)<br>Hence solve x2 - 10x + 3 = 0

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Answer:

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3 years ago

Which inequality best represents that ice cream at −2°C is cooler than ice cream at 3°C? Group of answer choices −3°C > 2°C −

ollegr [7]

Answer:

3°C > - 2°C

Step-by-step explanation:

Ice cream 1 = - 2°C

Ice cream 2 = 3°C

Lower temperatures are colder (cooler) than higher temperature values.

Hence, ice cream at - 2°C is cooler than ice cream at 3°C.

Hence, a temperature of 3°C is higher (greater) than - 2°C. Hence - 2°C is cooler (colder) than 3°C

Hence,

3°C > - 2°C

5 0

3 years ago

what does the slope of -1 tell you about thr relationship between lengths and widths of rectangles with perimeter 24?

NeX [460]

Using linear function concepts, the slope of -1 means that when one of the length/width is increased by 1, the other is decreased by 1.

<h3>What is a linear function?</h3>

A linear function is modeled by:

$y = mx + b$

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0.

In this problem:

The lengths and the widths are interchangeable, that is, either can be considered as the input or as the output.

The slope of -1 means that when the input in increased by 1, the output is decreased by -1, that is, when one of the length/width is increased by 1, the other is decreased by 1.

You can learn more about linear function concepts at brainly.com/question/24808124

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2 years ago

Find the directional derivative of at the point (1, 3) in the direction toward the point (3, 1). g

Anika [276]

Complete Question:

Find the directional derivative of g(x,y) = $x^2y^5$ at the point (1, 3) in the direction toward the point (3, 1)

Answer:

Directional derivative at point (1,3), $D_ug(1,3) = \frac{162}{\sqrt{8} }$

Step-by-step explanation:

Get $g'_x$ and $g'_y$ at the point (1, 3)

g(x,y) = $x^2y^5$

$g'_x = 2xy^5\\g'_x|(1,3)= 2*1*3^5\\g'_x|(1,3) = 486$

$g'_y = 5x^2y^4\\g'_y|(1,3)= 5*1^2* 3^4\\g'_y|(1,3)= 405$

Let P = (1, 3) and Q = (3, 1)

Find the unit vector of PQ,

$u = \frac{\bar{PQ}}{|\bar{PQ}|} \\\bar{PQ} = (3-1, 1-3) = (2, -2)\\{|\bar{PQ}| = \sqrt{2^2 + (-2)^2}\\$

$|\bar{PQ}| = \sqrt{8}$

The unit vector is therefore:

$u = \frac{(2, -2)}{\sqrt{8} } \\u_1 = \frac{2}{\sqrt{8} } \\u_2 = \frac{-2}{\sqrt{8} }$

The directional derivative of g is given by the equation:

$D_ug(1,3) = g'_x(1,3)u_1 + g'_y(1,3)u_2\\D_ug(1,3) = (486*\frac{2}{\sqrt{8} } ) + (405*\frac{-2}{\sqrt{8} } )\\D_ug(1,3) = (\frac{972}{\sqrt{8} } ) + (\frac{-810}{\sqrt{8} } )\\D_ug(1,3) = \frac{162}{\sqrt{8} }$

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3 years ago