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Alina [70]
3 years ago
13

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
vovikov84 [41]3 years ago
5 0

Answer:

1/2n-7

(0×3)+4

(p×5)-2

7+r

s+7

10-t

u-10

2×v

w×2

x÷5

5÷y

Step-by-step explanation:

Ulleksa [173]3 years ago
4 0

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>14) 1/2n - 7</em>

<em>15) 3o + 4</em>

<em>16) 5p - 2</em>

<em>17) 7 + r</em>

<em>18) s + 7</em>

<em>19) t - 10</em>

<em>20) 10 - u</em>

<em>21) 2v</em>

<em>22) 2w</em>

<em>23) x ÷ 5</em>

<em>24) 5 ÷ y</em>

<em />

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

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prohojiy [21]
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<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>

<span>Next, complete the square. </span>

<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>

<span>Also, for the x in the numerator </span>

<span>x = x + 1/2 - 1/2. </span>

<span>So </span>

<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>

<span>Integrate term by term to get </span>

<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>

<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>

<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>

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<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>

<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>

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Alenkasestr [34]
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7 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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