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Dimas [21]
3 years ago
12

(2x+3y-5)+(6x-4y+10) given x=2 and y=3

Mathematics
2 answers:
juin [17]3 years ago
8 0

(2x+3y-5)+(6x-4y+10) =

= (2*2 + 3*3 - 5) + (6*2 - 4*3 + 10)=

=(4 + 9 -5) + (12 - 12 + 10)=

= 8 + 10 =

=18

Elanso [62]3 years ago
3 0

The answer is 18.

Substitute the values of x and y into the expression.

(2x+3y-5)+(6x-4y+10)

(2·2+3·3-5)+(6·2-4·3+10)

(4+9-5)+(12-12+10)

(13-5)+(0+10)

8+10

18

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