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3 years ago

Which monomial is a perfect cube? 16x6 27x8 32x12 64x6

Mathematics

2 answers:

Marizza181 [45]3 years ago

7 0

Answer: The answer is (D) $64x^6.$

Step-by-step explanation: We are to select the correct monomial from the given options which is a perfect cube.

The first option is

$y=16x^6=2\times (8x^6)=2\times(2x^2)^3\\\\\Rightarrow \sqrt[3]{y}=2x^2\sqrt[3]{2}.$

So, this is not a perfect cube.

The second option is

$y=27x^8=x^2\times (27x^6)=x^2\times(3x^2)^3\\\\\Rightarrow \sqrt[3]{y}=3x^2\sqrt[3]{x^2}.$

So, this is not a perfect cube.

The third option is

$y=32x^{12}=4\times (8x^{12})=4\times(2x^4)^3\\\\\Rightarrow \sqrt[3]{y}=2x^4\sqrt[3]{4}.$

So, this is not a perfect cube.

The fourth option is

$y=64x^6=(4x^2)^3\\\\\Rightarrow \sqrt[3]{y}=4x^2.$

So, this is a perfect cube.

Thus, (D) $64x^6$ is the correct option.

Svetlanka [38]3 years ago

5 0

Which monomial is a perfect cube?16x627x832x1264x6

Its D

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snow_tiger [21]

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where we have x =we replace with 20

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if you need any clarifications please do tell me in the comment section.i would like to help more if you need help.thx

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maksim [4K]

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Step-by-step explanation:

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