Answer:
a. 0.75% per month
b. 2.25% per quarter 
c. 4.5% semi- annually
d. 9% yearly
Explanation:
a. Computing the effective interest rate per payment period for the payment schedule which is monthly:
Effective rate (monthly) = Nominal rate (r) / Compounded monthly (m)
where
r is 9%
m is 12
Putting the values above:
= 9% / 12
= 0.75% per month
b. Computing the effective interest rate per payment period for the payment schedule which is quarterly:
Effective rate (quarterly) = Nominal rate (r) / Compounded quarterly (m)
where
r is 9%
m is 4
Putting the values above:
= 9% / 4
= 2.25% per quarter 
c. Computing the effective interest rate per payment period for the payment schedule which is semi- annually:
Effective rate (semi- annually) = Nominal rate (r) / Compounded quarterly (m)
where
r is 9%
m is 2 (every 6 months)
Putting the values above:
= 9% / 2
= 4.5% semi- annually
d. Computing the effective interest rate per payment period for the payment schedule which is annually:
 Effective rate (annually) = Nominal rate (r) / Compounded yearly (m)
where
r is 9%
m is 1 (end of the year)
Putting the values above:
= 9% / 1
= 9% yearly
 
        
             
        
        
        
Answer:
![\left[\begin{array}{ccc}&January&February\\$beginning&45000&27500\\$receipts&97000&150000\\$disbursement&-114500&-163500\\$interest&0&0\\$subtotal&27500&14000\\$minimun&20000&20000\\$Financing&&\\$beginning&0&0\\$payment/loan&0&6000\\$ending&0&6000\\&&\\$ending cash&27500&20000\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26January%26February%5C%5C%24beginning%2645000%2627500%5C%5C%24receipts%2697000%26150000%5C%5C%24disbursement%26-114500%26-163500%5C%5C%24interest%260%260%5C%5C%24subtotal%2627500%2614000%5C%5C%24minimun%2620000%2620000%5C%5C%24Financing%26%26%5C%5C%24beginning%260%260%5C%5C%24payment%2Floan%260%266000%5C%5C%24ending%260%266000%5C%5C%26%26%5C%5C%24ending%20cash%2627500%2620000%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Explanation:
On January we collect the 85,000 from revenues and the 12,00 form marketable securities.
Then, we add up each disbursement:
Materials 50000
Labor       30000
Overhead (net of depreciation) 19,500
Selling and administrative 15000
Total 114,500
Then we solve for the cash balance and get the blaance as it is higher than 20,000 we do not need financing
Then, this value is the beginning cash for February. As the ending balance is 14,000 we will take 6,000 financing to reach the bare minimum of 20,000
 
        
             
        
        
        
Answer:
one should go to buy a car for $8000
Explanation:
given data 
car = $8,000
price down = $6,500
solution
As here Implied Warranty is the sale contract environment oral or written that provides some assurance that the products sold are suitable for trade and purpose. It arises from the operation of the law.
- Disclaimer is a statement that order are used to prevent the creation of a warranty or contract.
- After learning about the implied warranty and disclaimer, I was not going through the items sold.
- For someone who does not offer special consumer protection, they should go to buy a car for $8000.
 
        
             
        
        
        
Answer: True 
Explanation:
When a sector contributes a significant amount to GDP suffers a shock, the GDP of the nation will be shocked as well. Proportionally it goes that the greater the shock to the sector, the greater the shock to the GDP. 
For instance, Agriculture contributes a significant amount to GDP. If a drought were to hit that reduced harvests by 50%, the GDP will suffer a huge shock as well because the contribution from Agriculture will be significantly less. 
 
        
             
        
        
        
Answer:
<u>Maximum Amount that can be loanded = $4139619</u>
Explanation:
DSCR = NOI / Debt Service
Debt Service = Principal + Interest
NOI = $ 500000
Debt Service = 500000 / 125 % = $ 400,000
The loan would be ammortized monthly over a period of 25 years.
Monthly Payment or EMI
E = P×r×(1 + r)n/ ((1 + r)n - 1)
12E = 400,000 = [P×r×(1 + r)n/ ((1 + r)n - 1)] * 12
or, P = 400000 / 0.0966272500154557 = $4139619
<u>Maximum Amount that can be loanded = $4139619</u>