Answer:
quadrant I
Step-by-step explanation:
Can you rephrase the question please?
The correct answer is 55 1/50. Hope this helps!!
Answer:
The domain of the function i.e.
will be w > 0.
Hence, Domain = D = w > 0
Step-by-step explanation:
In order to find the domain of
, first we need to
make sure that denominator can not be zero. If the denominator is zero then the function will become undefined. So, the denominator i.e w can not have zero value.
Secondly, we are dealing with the function that involves the height (H) and width (w) of a rectangle. Since, height (H) and width (w) can not have minus and zero values.
So, In order to validate the function
, we must have to make sure that the value of width (w) can not have zero as well as negative value. The domain must to have to be anything greater than zero.
So, the domain of the function i.e.
will be w > 0.
Hence, Domain = D = w > 0
keywords: Domain, function
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<h2>
Answer with explanation:</h2>
A box contains 12 balls numbered 1 through 12.
Also the ball are drawn without replacement.
a)
The probability that the first ball had a smaller number on it.
i.e. the number on the first ball could be: {1,2,3}
Hence, the probability that the first ball had a smaller number on it is:
![\dfrac{3}{12}=\dfrac{1}{4}=0.25](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B12%7D%3D%5Cdfrac%7B1%7D%7B4%7D%3D0.25)
b)
The probability that the first ball has a even number on it is:
There are total 6 even numbers {2,4,6,8,10,12}
but 4 can't be considered as it comes on the second draw, so we are left with just 5 balls with even number.
Hence, the probability is:
![\dfrac{5}{12}=0.4166](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B12%7D%3D0.4166)