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Ganezh [65]
3 years ago
5

Jill is 4 years younger than half Janet’s age. If Janet is y years old, which expression describes how old Jill is?

Mathematics
1 answer:
balu736 [363]3 years ago
3 0
The answer is A 1/2y -4
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2 and a half cups of chocolate I think
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Subtract 4/5-1/5 i will give yall 87 points if yall answer
meriva

Answer:

\frac{3}{5}

Step-by-step explanation:

\frac{4}{5} - \frac{1}{5} = \frac{3}{5}

When the denominator of both fractions are the same, you can just calculate the numerators while leaving the denominator alone. In this case, 4-1=3 and the denominator is 5.

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Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
kotykmax [81]

Answer:

f'(x) = -\frac{2x}{1 - x^{2}}

Step-by-step explanation:

The derivative of an addition/subtraction of terms is the addition/subtraction of the derivatives of these terms.

The derivative of a constant is 0.

The derivative of a*x^{n} is a*n*x^{n-1}. The derivative of x^{3} is 3x^{2}, for example.

The derivative of the ln function:

If we have:

y = \ln{g(x)}

The derivative is

y' = g'(x)*\frac{1}{g(x)}

In this problem, we have that:

y = \ln{1 - x^{2}}

So g(x) = 1 - x^{2} and g'(x) = -2x

So the derivative to this function is

f'(x) = -\frac{2x}{1 - x^{2}}

8 0
3 years ago
10 cm<br> 22 cm<br> Someone help me with this question please
iren [92.7K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Given that a♥b =
kogti [31]
<span>First of all, write these in a way people can read them in the future. Don't make it so hard to help you.

Secondly:

Given that a♥b = 2a(32− b)

If a♥b = −23, solve for b in terms of a.

A) b = 16a + 32
B) b = 13a + 32
C) b = 12a + 32
D) b = 16a − 32

</span>-23 = 2a(32− b),  devide both sides by 2a -23/2a = 32 - b, subtract 32 from both sides -23/2a - 32 = -b, multiply both sides by -1  23/2a + 32 = b

verified:
b = 23/2a + 32 
-23 = 2a(32 − (23/2a + 32))
-23 = 2a(32 -23/2a -32)
-23 = 2a(-23/2a)
-23 = -23

Are you sure you copied this correctly?




4 0
3 years ago
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