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s2008m [1.1K]
3 years ago
12

Donald sells 760 marbles everyday. He sells each marble for 1.5 dollars. For how many days does Donald need to sell marbles to e

arn 3420 dollars?
A) 2 days
B) 12 days
C) 6 days
D) 3 days
Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

Donald needs 3 days to earn 3420 dollars

Step-by-step explanation:

Donald sells 760 marbles everyday. He sells each marble for 1.5 dollars

amount collected in one day= 760 \cdot 1.5=1140 dollars

In one day the amount earned is 1140 dollars

we need to find the number of days needs to earn 3420 dollars

Number of days needed is \frac{3420}{1140}=2.842

So its around 3 days

Donald needs 3 days to earn 3420 dollars

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Michael has a collection of 124 sports cards. He hopes to sell the collection in packs of 4 cards and make $496.31 when all the
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Answer:

the price that Michael charge per pack is $16.01

Step-by-step explanation:

The computation of the price that Michael charge per pack is as follows:

= 124 sports card ÷ 4 cards

= 31 packs

Now the charge per pack would be

= $496.31 ÷ 31 packs

= $16.01

hence, the price that Michael charge per pack is $16.01

The same is to be considered

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3 years ago
You need at least $535 to go on a trip to California. You have already saved $200.
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4 years ago
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Which statements are true for the following expression?
Vlad1618 [11]

Answer:

2.) The solution is the product of two factors

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Step-by-step explanation:

because :

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Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS
olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....

where, n = number of trials (samples) taken = 36 couples

            r = number of success

            p = probability of success which in our question is probability

                   of a girl, i.e.; p = 0.5

<em><u>Let X = Numbers of girls in groups of 36 births </u></em>

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

         <u>Mean</u>, E(X) = n \times p = 36 \times 0.5 = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

        <u>Standard deviation</u>, S.D.(X) =  \sqrt{n\times p\times (1-p)}

                                                      =  \sqrt{36\times 0.5\times (1-0.5)}

                                                      =  3

3 0
3 years ago
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