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statuscvo [17]
3 years ago
7

Solve the equation Square root X+4-3=1 for the variable. show each step of the solution process

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0
You want to solve for x first:
x+4-3=1        (combine 4 and -3)
x+1=1           (subtract 1 on both sides)
x=0        
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I really need help please <33​
Anvisha [2.4K]

Tonya's homework assignment has four problems a, b, c, d. Her teacher instructed her to simplify each expression and then find out its value. The value of a is 3/28, the value of b is 1/2, the value of c is 15/56 and the value of d is 1/15.

Each problem has two fractions. They are given below and should be simplified.

a) 2/7 × 3/8 = 1/7 × 3/4 = 3/28

b) 2/3 × 3/4 = 1/1 × 1/2 = 1/2

c) 3/7 × 5/8 = 15/56

d) 3/10 × 2/9 = 1/5 × 1/3 = 1/15

To know more about fractions:

brainly.com/question/24503096

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3 0
1 year ago
Is 976 -522 more or less than 400? Explain how you can tell without actually subtracting.
liq [111]
You can round 976 to 1000 and 522 to 500. So it would be
1000 - 500 = 500. The answer you would get after subtracting 976-522 would be more than 400 if you round it.
3 0
3 years ago
Read 2 more answers
In 4.59 what does the nine stand for?
Kisachek [45]

The 9 stands for hundredths

4 0
2 years ago
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PLEASE HELP! THANK YOU! :D
Ostrovityanka [42]
I think it’s C. Sorry if I’m incorrect
6 0
3 years ago
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HELP PLEASE,<br><br> Part a of the question was posted earlier on.
Elanso [62]
\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7&#10;\\\\\\&#10;\lim\limits_{x\to 6}~(6)+7=13&#10;\\\\\\&#10;\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\&#10;\textit{the same limit as }x+7
3 0
2 years ago
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