<h2>
Hello!</h2>
The answer is: 
<h2>
Why?</h2>
Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.
The range is where the function can exist in the vertical axis when we assign values to the variable.
First:
: Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)
Second:
: Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.
Third:
: Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).
Fourth:
: Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).
I attached a pic of the csc function graphic where you can verify the answer!
Have a nice day!
Answer:
Step-by-step explanation:
h=16t^2+98=?
subtract 98 from both sides to get
h-98=16t^2
(the 98 on the right cancels)
now divide by 16 on both sides
h-98/16=t^2
(the 16 on the right cancels)
lastly take the square root on both sides
square root(h-98/16)= t
if you know what h is fill it in and it will give you your answer
Im not 100% sure!!
Answer:
D
Step-by-step explanation:
Answer:
S₃ = 37
Step-by-step explanation:
given a₁ = 16 and r = 
, then
a₂ = a₁ × = 16 × = 12
a₃ = a₂ × = 12 × = 9
then
S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37
