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hichkok12 [17]
3 years ago
9

What is the solution for this problem?

Mathematics
1 answer:
Over [174]3 years ago
8 0
First of all let's rearrange the equation for the given line:

4x + 7y + 3 = 0
7y = -4x - 3
y = (-4/7)x - 3/7
Now we know that the gradient of the line is -4/7

The gradients of two perpendicular lines multiply by each other to give -1, ie.
(-4/7)*m = -1
m = -1/(-4/7)
= 7/4, therefor the gradient of the perpendicular line is 7/4

Now we can substitute this and the point (-2, 1) into the equation y - y1 = m(x - x1)
y - 1 = 7/4(x - (-2))
y = 7/4x + 7/2 + 1
y = 7/4x + 9/2

If we look at the given answers then C is correct, since 9/2 = 18/4 and so the equation may also be written as y = 7/4x + 18/4
You might be interested in
What multiples to 42 and adds to -2
solniwko [45]

Answer:

Step-by-step explanation:

xy = 42

x+y = - 2                   Substitute into the top equation

y = -2 - x                   Put in for y

x(-2 - x) = 42             Remove the brackets

-2x - x^2 = 42           Subtract 42 from both sides.

-2x - x^2 - 42 = 0      Put in the more normal order.

-x^2 - 2x - 42 = 0      Multiply by -1

x^2 + 2x + 42 = 0

This cannot be factored. It gives complex roots as it is written. I will give you the answer but I kind of doubt the question is correct.

x1 = - 1 + 6.40i

x2 = -1 - 6.40i

Leave a comment if you have a correction.

4 0
4 years ago
Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). Include your work in you
asambeis [7]
2-1=1
y-y1=m(x-x1)
y-1=1(x-2)
5 0
3 years ago
Read 2 more answers
30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now
barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0
1 year ago
Wich expression is equivalent to 3 (m-3) +4
hoa [83]
3( m - 3) + 4 = 3m - 9 + 4 = 3m - 5
8 0
3 years ago
A school club wants to buy shirts for each of its 38 members. Each shirt cost $23. About how much money will all the shirts cost
lana66690 [7]

Answer: $874


Step-by-step explanation: multiply 23 by 38 to get the total cost


5 0
3 years ago
Read 2 more answers
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