Write all puppies are cute as a conditional

2 answers:

7 0

There are three different kinds of conditional sentences, here is a condition sentence type three for your words:
If I had seen all the puppies, I would have said they where cute
I hope that as what you're looking for! :)

Oksana_A [137]4 years ago

7 0

Answer:

All puppies are cute as a conditional

Step-by-step explanation:

You might be interested in

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,

m_a_m_a [10]

The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

Part A: The starting point is in the second quadrant and the finishing point is in the fourth quadrant.

Part B: The starting point and the check point are on different quadrant. Both points are on the same horizontal line.

Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the x and y-values in the quadrants are;

$\begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right]$

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

coordinate is negative and the y-coordinate is positive, the quadrant of the

starting point is quadrant II (the second quadrant).

The quadrant of the starting point is the second quadrant.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

The quadrant of the finishing point is the fourth quadrant.

Part B: The location of the checkpoint is; (5.3, 1)

The difference is that the x-value of the checkpoint is positive while the x-value of the starting point is negative, and they are therefore on different quadrants.

The similarity is that, the magnitude of the x, and y values of the coordinates of the check point and the starting point are the same. Therefore, the checkpoint and the starting point are on the same horizontal line.

Learn more about the Cartesian coordinate plane here:

brainly.com/question/17877300

brainly.com/question/16177011

8 0

3 years ago

Simplify. 10 / 7 k + 11 / 7 - 2 k + 2/7 + 2/7 k -6

Nikolay [14]

As written, this is

$\dfrac{10}{7}k+\dfrac{11}{7}-2k+\dfrac{2}{7}+\dfrac{2}{7}k-6=\left(\dfrac{10}{7}-2+\dfrac{2}{7}\right)k+\left(\dfrac{11}{7}+\dfrac{2}{7}-6\right)\\\\=\dfrac{10-14+2}{7}k+\dfrac{11+2-42}{7}\\\\=-\dfrac{2}{7}k-\dfrac{29}{7}$