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Vika [28.1K]
3 years ago
12

A typical human cell is approximately 12.00 μm in diameter and enclosed by a membrane that is 5.000 nm thick. (a) What is the vo

lume of the cell including the membrane? (b) What is the volume of the cell membrane? (c) What percent of the total volume does its membrane occupy? To simplify the calculations, model the cell as a sphere. Enter your answers using four significant figures.
Biology
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

a) 7243.6069\\

b) 9.0469

c) 0.1248%

Explanation:

We know that 1 nm is equal to 0.001μm

Given,

a) Radius of human cell

= 12 μm

b) Thickness of cell membrane

= 5nm = 0.005μm

c) Radius of human cell including the thickness of cell membrane

= 12 + 0.005\\= 12.005\\μm

a) Volume of the cell including the membrane

\frac{4}{3} \pi r^{3} \\= \frac{4}{3} *(3.14)* (12.005)^{3}\\= 7243.6069 cubic μm

b) Volume of the cell membrane

Volume of cell without membrane

\frac{4}{3} \pi r^{3} \\= \frac{4}{3} *(3.14)* (12)^{3}\\= 7234.56 cubic μm

Volume of cell membrane only is equal to

7243.6069 - 7234.56\\= 9.0469 cubic μm

b) What percent of the total volume does its membrane occupy

The percent of the total volume occupied by  its membrane is equal to

\frac{9.0469}{7243.6069} * 100\\= 0.1248%

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