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Umnica [9.8K]
4 years ago
14

Takumi started studying how the number of branches on his tree changes over time.

Mathematics
1 answer:
Musya8 [376]4 years ago
8 0

Answer:

Grows, Factor of 2

Step-by-step explanation:

The relationship between the elapsed time, t, in years, since Takumi started studying his tree, and the total  number of its branches, N(t), is modeled by the function:

N(t) = 63. 2^t

For illustration, let us take the growth for the first three years after he started studying the number of branches.

When \:t=1, N(1) = 63. 2^1=126\\When \:t=2, N(2) = 63. 2^2=252\\When \:t=3, N(3) = 63. 2^3=504\\504\div 252=252\div 126=2

We notice that for each subsequent year, the number of branches doubles.

Therefore:

Every year, the number of branches  <u>grows</u> by a factor of <u>2.</u>

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What is 2x + 7x + 8a + 9a
nlexa [21]

Answer: 9x + 17a

Step-by-step explanation:

2x + 7x + 8a + 9a

2x+7x= 9x

8a+9a= 17a

= 9x +17a

8 0
3 years ago
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The outer and inner triangles are both equilateral and the circle touches all three sides of the outer triangle. If the area of
Brrunno [24]

Answer:

The area of outer Δ = 40 cm²

Step-by-step explanation:

∵ Area of the small triangle = 10 cm²

If we join the center of the circle with the 3 vertices of the inner Δ

These 3 segments are the radii of the circle

Now the inner triangle has 3 isosceles Δ their sides are r , r and s1 with vertex angle 120° ⇒ (360° ÷ 3 = 120°)

Where r is the radius of the circle and s1 is the side of the inner triangle

<em>By using cosine rule</em>

(s1)² = r² + r² - 2r²cos120 = r² + r² - 2r² (-0.5) = r² + r² + r² = 3r²

∴ s1 = r√3

∵ The radius of the circle ⊥ to the side of the outer Δ because the side of the outer Δ is a tangent to the circle

If we join a vertex of the outer Δ with the center of the circle

We will have a right angle triangle of two legs r and half s2 with angle 60° (120° ÷ 2 )between them ⇒ s2 is the side of outer Δ

∴ tan 60° = 1/2 (s2) ÷ r ⇒ √3 = 1/2 (s2) ÷ r = (s2)/2r

∴ s2 = 2r√3

∴ s2 : s1 = 2r√3 ÷ r√3 = 2 : 1

∴ The side of the outer Δ is double the side of the inner Δ

<em>By using similarity ratio</em>

A2/A1 = (s2/s1)² ⇒ A2 and A1 are the areas of outer and inner triangles

∴ A2 : A1 = (2/1)² = 4/1  

∴ A2 = 4 A1

∴ A2 = 4 × 10 = 40 cm²

5 0
3 years ago
The managers of franks snack shack buys hamburgers in packages of 30 and hamburger buns in packages of 24. He cannot buy part of
Andreas93 [3]

Answer:

He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24

Step-by-step explanation:

First we have to calculate the least common multiple (LCM) of 24 and 30

We will calculate the LCM of 24 and 30 by prime factorization method

24 = 2*2*2*3 = 2^{3} * 3^{1}

30 = 2*3*5 = 2^{1} *3^{1}* 5^{1}

LCM = 2^{3}* 3^{1}*5^{1}

LCM = 120

So number of hamburger buns = 120

Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30

4 0
3 years ago
Jacqueline is checking her bicycle’s wheel. The wheel has a radius of 20 cm, and its center is 51 cm above the ground. Jacquelin
Alex777 [14]

Answer:

h = 36.9 cm

Step-by-step explanation:

The function given to us is:

h(t) = 51 + 20 sin(225t)

Where h(t) is the function of the height in centimeters while t represents the time in seconds.

We have to find the height h(t) when the time is equal to 19 seconds.

Substitute t=19 into the given function

h(19) = 51 + 20 sin(225(19))

h(19) = 51 + 20 sin(4275)

h(19) = 51 + 20 (-0.7071)

h(19) = 51 + (-14,1421)

h(19) = 36.8579 cm

Rounding off to nearest 10th

h = 36.9 cm

6 0
4 years ago
Find the equation of the line.<br> Use exact numbers.
Marina CMI [18]

Answer:

Y=3x+3

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8 0
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