The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
<h3>How to type the ordered pairs?</h3>
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
Read more about exponential functions at:
brainly.com/question/2456547
#SPJ1
Answer:
The answer is B, d=45t
Step-by-step explanation:
i just did it and got it correct
hope it helps and good luck :)
Answer: x=3
Step-by-step explanation: This is a porportion, meaning that the numbers are set equal to each other. Look at your denominators, 4 and 8? What do they have in common? In this case, they have a factor of 2 in common, and 8 is 4x2. So then we look at the numerators now. What times 2 equals to 6? Your answer then becomes 3.
Answer: 14a^5+14a^4-10a^3-16a
Step-by-step explanation: sorry if it confusing but ^3 as an example is supposed to be the mini number that goes on top of that number.
-hope this helps