Answer:
69,42069,420
Step-by-step explanation:
Answer:
Perimeter of given regular hexagon is <em>48.5 ft</em>.
Step-by-step explanation:
Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.
<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.
As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.
In other words,
are equilateral
.
Area of an equilateral
is defined as
:
![\dfrac{\sqrt{3}}{4} \times a^{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%20%5Ctimes%20a%5E%7B2%7D)
Where <em>a </em>is the side of
.
Area of hexagon = ![6 \times \dfrac{\sqrt{3}}{4}\times a^{2}](https://tex.z-dn.net/?f=6%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5Ctimes%20a%5E%7B2%7D)
We are given that area of hexagon = 169.74 ![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
Let <em>s </em>be the side of hexagon.
![\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft](https://tex.z-dn.net/?f=%5CRightarrow%206%20%5Ctimes%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B4%7Ds%5E%7B2%7D%20%3D%20169.74%20ft%5E%7B2%7D%5C%5C%5CRightarrow%20s%20%3D%208.08%20ft)
A regular Hexagon is made up of 6 equal sides, so
Perimeter of a regular hexagon = ![6 \times side](https://tex.z-dn.net/?f=6%20%5Ctimes%20side)
Perimeter = ![6 \times 8.08](https://tex.z-dn.net/?f=6%20%5Ctimes%208.08)
![\Rightarrow 48.5 ft](https://tex.z-dn.net/?f=%5CRightarrow%2048.5%20ft)
So, perimeter of given regular hexagon is
.
Answer:
-4608
Step-by-step explanation:
Answer:
There is no graph
Step-by-step explanation:
we need a pic of the graph to answer
400 is the estimate of 440