Good morning ☕️
Answer:
<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ =
0</h3>
Step-by-step explanation:
Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰
S = i¹ + i² + i³ + . . . + i⁹⁹ + i¹⁰⁰
S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀
then, S is the sum of 100 consecutive terms of a geometric sequence (an)
where the first term a1 = i¹ = i and the common ratio = i
FORMULA:______________________
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then
or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1 (we know that i⁴ = 1)
Hence
S = 0
To answer you get the same denominator so multiply both denominators with each other and do the same with the top so 25 will be at both bottoms and well 15/25 and 8/25. Then solve
Answer:
Step-by-step explanation:
2/80 is equivalent
you can also just multiply the numerator and denominator to find out what else is equivalent.
Off the top of my head i can tell that B) 3 and A) -1 are two possible roots, you can plug it into a calculator and situate put if there is more