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pav-90 [236]
3 years ago
9

Can someone help me please

Mathematics
2 answers:
maks197457 [2]3 years ago
8 0
<span>8y - 3y = 5y because you just subtract and then add y at the end</span>
ELEN [110]3 years ago
3 0
9. 5y
10.10x^2-1 
not done 
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I’m having trouble with this. There should be an image or a link attached.
alina1380 [7]

Answer:

1.) n-10

2.) 4 / x=x (dont trust me on this)

3.) -8n+1

4.) 1/2 - 19 ( dont trust me on this)

5.)3/5-21 or 3/5>21

6.)x^+15

Step-by-step explanation:

I tried double check  it

its been awhile

5 0
2 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
10 months ago
Which statements are true about the interquartile range? Select all that apply.
PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

  • Put the numbers in order
  • Find the median Place parentheses around the numbers before and after the median
  • Find Q1 and Q3 which are the medians of the data before and after the median of all data
  • Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>

<em />

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>

<em />

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)

E. The data values should be listed in order before trying to find the interquartile range  ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>

4 0
3 years ago
Read 2 more answers
What is the answer to there are 56 students going to the game . The coach puts 7 students in each van. How many vans are needed
MAVERICK [17]

Answer:

56:7 = 8

Step-by-step explanation:

<h2 />
7 0
3 years ago
If the vertex of a parabola is negative for 6 and the other point of the curve is (-3,14) what is the coefficient of the squared
Anton [14]

Answer:

coefficient of the square is a.6

6 0
3 years ago
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