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3 years ago

15

What is the measure of angle B if angle BCD is 100

1 answer:

JulijaS [17]3 years ago

8 0

The triangle is isosceles so the angle measurements of angle A and C is 80 degrees. So:

180 - (80 + 80)= 20

Answer: 20 degrees

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find the cost of a car using the installment plan if the down payment is $1,500 and the monthly payments are $385 for 4 years, s

Blizzard [7]

Well, if this is assuming there is no tax on the vehicle and it is fully paid off by the end of the payments, an equation can be set up like the following. 385x+1500=C, x being months and C being total cost. 385(12*4)+1500= C, 385(48)+1500=C, 18480+1500=C, 19980=C.

8 0

3 years ago

Jorge bought 16 apples for $8.00.

maks197457 [2]

assuming that 0 apples costs 0 dollars

and 16 apples costs $8

so we have the points

(0,0) and (16,8) in form (x,y)

graph below

5 0

3 years ago

50+51+52+...+101=...<br>Can you help me? I do not understand

Dmitriy789 [7]

Suppose

$S=50+51+52+\cdots+100+101$

At the same time, we can write

$S^*=101+100+99+\cdots+51+50$

Note that $S=S^*$ (just reverse the sum). Let's pair the first terms of $S$ and $S^*$ , and the second, and the third, and so on:

$S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)$

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

$S+S^*=52\cdot151$

But $S=S^*$ , as we pointed out, so

$2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926$

5 0

3 years ago

What is the slope of (-7,-1) and (3,8)? Pls show your work

kondor19780726 [428]

Answer:

$m=\frac{9}{10}$

Step-by-step explanation:

To find the slope between any two points, we can use the following slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Let (-7, -1) be (x₁, y₁) and let (3, 8) be (x₂, y₂). Substitute them into the slope formula:

$m=\frac{8-(-1)}{3-(-7)}$

Evaluate:

$m=\frac{9}{10}$

Therefore, the slope between the two points is 9/10.

6 0

3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago