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son4ous [18]
3 years ago
15

During the past year in the maternity ward of a hospital in a large city, 1,254 males were born and 1,462 females. If we can ass

ume this data is representative of all births in the city, what is the probability that the next baby born in this particular hospital will be a boy? What is the probability that it will be a girl? give your answer as fractions reduced to lowest terms.
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0
\frac{1,254}{1,254+1,462} /  \frac{1,462}{1,254+1,462}\\ \frac{1,254}{2,716} / \frac{1,462}{2,716}\\\frac{627}{1,358} /  \frac{731}{1,358}

Chance of boy: 627/1,358

Chance of girl: 731/1,358
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beks73 [17]

The result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

<h3>How to evaluate the expression?</h3>

The expression is given as:

\sin^2(\theta) * (1 + \cos(\theta))

Express \sin^2(\theta) as 1 - \cos^2(\theta).

So, we have:

\sin^2(\theta) * (1 + \cos(\theta)) =  (1- \cos^2(\theta)) * (1 + \cos(\theta))

Open the bracket

\sin^2(\theta) * (1 + \cos(\theta)) =  1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Express 1 as cos°(Ф)

\sin^2(\theta) * (1 + \cos(\theta)) =  cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Hence, the result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

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