Question

The length of a rectangle is 2 units greater than the width. The area of the rectangle is 24 square units. What is it's width?

Answer 1

Answer:

Width = 4 units

Step-by-step explanation:

Let us pose the width as w, and the length as l. If the length is 2 units greater than the width, consider the following;

$l = 2 + w,\\\\w = width,\\l = length$

The area of this rectangle can be determined through length * width / l * w, and is given to be 24 square units. We can say l = 2 + w instead, solving for the width ( w );

$( 2 + w ) * w = 24,\\2w+w^2=24,\\\left(w-4\right)\left(w+6\right)=0,\\w = 4, w = - 6\\\\Solution - width = 4 units$

As the width couldn't be a negative value, we had to take the positive of 4 and - 6, which was 4 units.

Answer 2

Answer:

4 units

Step-by-step explanation:

Length would be 6 units and width would be 4 units

6*4 = 24 proving my claim to be true