Here are the scores of 17 students on a history test. 62, 65, 66, 67, 67, 76, 77, 78, 79, 80, 86, 88, 88, 89, 90, 91, 92 Notice
creativ13 [48]
I added a picture with it for you. I suggest that before this becomes an issue you take some time and study box and whisker plots, because they tend to show up on a lot of standardized math tests.
Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
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The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
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That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
20/3 ounces of water is added.
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.
You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
Wouldn't the ratio from length to width be 8?
