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4 years ago

Evaluate -a. a=2.2 need help

Mathematics

2 answers:

Fed [463]4 years ago

8 0

A = 2.2

Multiply each side of the equation by -1 :

-a = -2.2

Dvinal [7]4 years ago

8 0

If a = 2.2

Multiply both sides by a (-) sign, we get

- a = -2.2 Answer

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Naily [24]

Answer:

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Step-by-step explanation:

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3 years ago

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What expressions are equivalent to j+j+2k

Nookie1986 [14]

Answer:

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3 years ago

prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

6 0

3 years ago

The sum of a number z divided by three and the number

charle [14.2K]

the required algebraic expression is: $\frac{z}{3}+z$

Step-by-step explanation:

We need to write the algebraic expression of the sum of a number z divided by three and the number

Let the number be z

a number z divided by three: $\frac{z}{3}$

the sum of a number z divided by three and the number: $\frac{z}{3}+z$

So, the required algebraic expression is: $\frac{z}{3}+z$

Keywords: Algebraic expression

Learn more about Algebraic expression at:

#learnwithBrainly

5 0

3 years ago

Which one is right for this please

irga5000 [103]

Answer:

C is correct

Step-by-step explanation:

To factor:

4x^2 + 12x + 5

(4x^2 + 2x)(10x + 5)

2x(2x + 1) + 5(2x + 1)

Then, take the outside numbers make them their own group:

2x + 5

(2x + 5)(2x + 1)

Therefore, it’s (2x + 1)(2x + 5)

8 0

3 years ago